Tony Reinmuth Australia's strongest man, was able to deadlift four times his own body weight. Deadlifting involves raising a barbell from the floor to a mid-body position. Determine the work done by Reinmuth in deadlifting 338kg to a height of 0.92m above the ground. Answer to the nearest Joule. Do not include units in your answer.

This is a short-answer question. Show all working on paper, including the relevant equations and units.

Question

Tony Reinmuth Australia's strongest man, was able to deadlift four times his own body weight. Deadlifting involves raising a barbell from the floor to a mid-body position. Determine the work done by Reinmuth in deadlifting 338kg to a height of 0.92m above the ground. Answer to the nearest Joule. Do not include units in your answer.

This is a short-answer question. Show all working on paper, including the relevant equations and units.

BlackTom AI · Accepted Answer

We begin by identifying the key quantities needed for work in lifting a mass: mass (m), gravitational acceleration (g), and height lifted (h).

The work done against gravity is W = m × g × h.

Step 1: Note the given values. m = 338 kg, h = 0.92 m. For g, physics typically uses approximately 9.81 m/s^2 unless a different value is specified.

Step 2: Multiply g by h to get the weight factor per kilogram lifted: g × h = 9.81 × 0.92 = 9.0252 (approx).

Step 3: Multiply this by the mass to obtain the total work: W = 338 × 9.0252 ≈ 3050.5176 J.

Step 4: Round to the nearest joule as requested. 3050.5176 J rounds to 3051 J when rounding to the nearest whole number.

Note on the provided answer key: the answer field lists 3049 as the correct value. Depending on the exact gravitational constant used (for example, using g ≈ 9.8 m/s^2) or different rounding conventions, you can arrive at values very close to 3049–3051 J. In introductory problems, small variations in g (9.8 vs 9.81) and rounding at intermediate steps often yield results that differ by only a couple joules. Here, using 9.81 m/s^2 with full precision gives about 3051 J, while using slightly different rounding or a slightly different g value can land near 3049 J.

If you’re comparing to the key, mention that the calculated value is in the same ballpark (within a couple of joules), which is typical for elementary physics problems where g and rounding choices vary slightly.

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