Question17 What does the code below do? def my_function(n): total = 0 while True: total += 5 if total = n: break return total Select one alternative: It generates an infinite loop. It returns the sum of all numbers from 1 to n. It always returns 3. It returns the smallest multiple of 5 that is greater than or equal to n. ResetMaximum marks: 2 Flag question undefined

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Question17 What does the code below do? def my_function(n): total = 0 while True: total += 5  if total >= n: break return total Select one alternative: It generates an infinite loop. It returns the sum of all numbers from 1 to n. It always returns 3. It returns the smallest multiple of 5 that is greater than or equal to n. ResetMaximum marks: 2 Flag question undefined

BlackTom AI · Accepted Answer

Question: What does the code below do? def my_function(n): total = 0 while True: total += 5  if total >= n: break return total

Options:
1) It generates an infinite loop.
2) It returns the sum of all numbers from 1 to n.
3) It always returns 3.
4) It returns the smallest multiple of 5 that is greater than or equal to n.

Option 1: It generates an infinite loop. This is not correct because the loop contains a break condition: if total >= n: break. Each iteration increases total by 5, so eventually the condition will be met and the loop will exit unless n is not a positive number. Therefore, the loop is not infinite for typical positive n.

Option 2: It returns the sum of all numbers from 1 to n. This would require accumulating a sequence like 1, 2, ..., n. Here the code increments total by 5 each time, not by 1, and it stops based on total reaching or exceeding n rather than summing 1 through n, so this is incorrect.

Option 3: It always returns 3. There is no mechanism in the code that fixes the return value at 3; the return value depends on n via the loop condition total >= n, so this statement is false.

Option 4: It returns the smallest multiple of 5 that is greater than or equal to n. This matches the behavior: starting at total = 0, total increases by 5 each iteration, and the loop stops when total >= n, yielding the minimal 5-multiple that is at least n. This is the correct interpretation.

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