题目
CHEM1011 (ND) Lecture quiz: Week 6
匹配题
Match the following descriptors about a central atom in a molecule to its shape as described by VESPR 1: 3 Connected Atoms, No Lone Pairs 2: 3 Connected Atoms, One Lone Pair 3: 4 Connected Atoms , No Lone Pairs
选项
A.Trigonal Planar
B.Trigonal Pyramidal
C.Tetrahedral
查看解析
标准答案
Please login to view
思路分析
Let's lay out the task in our own terms: we are matching each descriptor of a central atom to the corresponding molecular shape in VSEPR.
Option 1 describes a central atom with 3 connected atoms and no lone pairs. When three atoms are bonded to the central atom and there are no nonbonding electron pairs, the electron geometry and the molecular geometry are both trigonal planar, with bond angles ab......Login to view full explanation登录即可查看完整答案
我们收录了全球超50000道考试原题与详细解析,现在登录,立即获得答案。
类似问题
Using the VSEPR model, what are the respective electron-domain geometries of carbon dioxide (CO2) and ammonia (NH3)? I: CO2 [ Select ] trigonal bipyramidal octahedral trigonal planar tetrahedral linear II: NH3 [ Select ] tetrahedral trigonal planar octahedral linear trigonal bipyramidal 13A
The electron domain geometry of IF4+ is __________.
Question at position 20 Which of the listed compounds is part of the tetrahedral electron group arrangement? SO2 AsF3 CO2 ICl4–
Question at position 26 Use VSEPR theory to predict the molecular shape of SOCl2? Trigonal pyramidalSquare pyramidal Square planar Tetrahedral Bent
更多留学生实用工具
希望你的学习变得更简单
加入我们,立即解锁 海量真题 与 独家解析,让复习快人一步!