How many valence electrons are in the electron-dot structure of SeF2?

Question

BlackTom AI · Accepted Answer

To determine the number of valence electrons in the electron-dot (Lewis) structure for SeF2, we first identify the valence electrons contributed by each atom.
Option 26: This would imply a total that is not consistent with the usual valence counts for Se (group 16, valence 6) and F (group 17, valence 7). It miscounts either core electrons or misattributes electrons to valence.
Option 20: This matches the standard calculation: Se has 6 valence electrons, each F has 7 valence electrons, and there are two fluorine atoms, so total valence electrons = 6 + 2×7 = 6 + 14 = 20. This is the correct total for the Lewis structure.
Option 42: This number is too large for a molecule consisting of one Se atom bonded to two F atoms when only valence electrons are counted; it would imply counting core electrons or extra electron pairs beyond the valence shell, which is not how Lewis structures are drawn.
Option 8: An octet for selenium alone is not the full picture here; the molecule involves selenium bonded to two fluorines, so we must include both selenium’s and fluorines’ valence electrons, not just a minimal octet for Se.
Option 33: This value does not correspond to the standard valence-electron count for SeF2 and appears to be an arbitrary sum that doesn’t reflect the actual group-number electron counts for Se and F in this compound.

SP25: CHEM-30A Sec 01 - Intro Chem Final Exam

How many valence electrons are in the electron-dot structure of SeF2?

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