以下哪个 JavaScript 条件语句的结果为true

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BlackTom AI · Accepted Answer

Question: Which JavaScript conditional statement evaluates to true?
Option 1: '（“0” == 假）' interprets as '"0" == false'. In JavaScript, the loose equality operator (==) performs type coercion. false becomes 0, and the string '0' is coerced to the number 0 as well. Therefore, 0 == 0 evaluates to true. 
Option 2: '（1 == 真）' interprets as '1 == true'. Here, true is coerced to 1, and the string '1' is coerced to the number 1 as well. Consequently, 1 == 1 evaluates to true. 
A couple of subtle points to note: with ==, JavaScript converts both operands to a common type before comparing, which is why both comparisons can yield true even though the operands start as a string and a boolean. If you were using the strict equality operator (===), the results would differ because no type coercion would occur. For example, '0' === false would be false, since the types (string vs boolean) do not match, and '1' === true would also be false for the same reason. The key concept here is understanding how loose equality triggers type coercion among strings, numbers, and booleans.

4510_COMP_SCI_X_0019 测验 2

以下哪个 JavaScript 条件语句的结果为true

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