题目
题目
多重下拉选择题

For the truss shown, determine by inspection whether the forces in AB, AC, BC, BD and BE are tensile, compressive or zero. The force in member AB is Blank 1 Question 5[select: , zero, compressive, tensile] The force in member AC is Blank 2 Question 5[select: , zero, compressive, tensile] The force in member BC is Blank 3 Question 5[select: , zero, compressive, tensile] The force in member BD is Blank 4 Question 5[select: , zero, compressive, tensile] The force in member BE is Blank 5 Question 5[select: , zero, compressive, tensile]

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Question restatement: - Determine by inspection whether the forces in AB, AC, BC, BD, and BE are tensile, compressive, or zero in the truss shown. The given selections are: AB = Blank 1 (one of: zero, compressive, tensile), AC = Blank 2 (zero, compressive, tensile), BC = Blank 3 (zero, compressive, tensile), BD = Blank 4 (zero, compressive, tensile), BE = Blank 5 (zero, compressive, tensile). Option-by-option analysis: Option for AB (Blank 1): zero, compressive, or tensile - Consider joint A. It connects only two members: AB (slanted) and AC (horizontal base). There is no external load directly applied at A. With only two members meeting at a joint that has no ......Login to view full explanation

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Question text 13Marks PROBLEM 3 Consider the truss shown below in Figure P3a. It is loaded with seven external forces, labelled [math: F1] F_1 to [math: F7] F_7 , acting at the nodes of the truss. The forces are all positive non-zero forces acting in the directions shown. Figure P3a. Truss with applied forces. (a) How many zero force members are there for this truss loading condition? (1 mark) Answer 1[input] zero-force members (b) Consider the same truss in Figure P3a (above). Select the best classification of its stability and determinacy by selecting from the options below. (1 mark) Answer 2[select: , Stable but statically indeterminate, Unstable and statically determinate, Stable and statically determinate, Unstable and statically indeterminate, Overconstrained but unstable] (c) Now consider the truss shown below in Figure P3b. It is loaded with four external forces, labelled [math: Q1] Q_1 to [math: Q4] Q_4 , acting at the nodes of the truss as shown. Determine the reaction forces [math: Hx] H_x and [math: Hy] H_y at the pin support at Node H, and the vertical reaction [math: Oy] O_y at the horizontal roller support, Node O. Note: all reactions are positive in the direction of x and y axes, respectively, and a counterclockwise moment is considered positive. (5 marks) [math: d=10m] d = 10 \, \text{m} [math: h=15m] h = 15 \, \text{m} [math: θ=40∘] \theta = 40^\circ [math: Q1=200kN] Q_1 = 200 \, \text{kN} [math: Q2=Q3=115kN] Q_2 = Q_3 = 115 \, \text{kN} [math: Q4=200kN] Q_4 = 200 \, \text{kN} Figure P3b. Truss with applied forces. Horizontal reaction at H ([math: Hx] H_x ) = Answer 3[input] kN Vertical reaction at H ([math: Hy] H_y ) = Answer 4[input] kN Vertical reaction at O ([math: Oy] O_y ) = Answer 5[input] kN (d) Now consider the same truss with different forces applied as shown in Figure P3c and listed below. Force [math: P4]P_4 is applied at Node E in the direction parallel with member EL, as shown in the figure. All other external forces are applied vertical (downwards) at the nodes. The reaction forces at the pin joint at H and the horizontal roller at O are provided to you for this loading configuration. (6 marks) Figure P3c. Truss with applied forces. [math: d=10m] d = 10 \, \text{m} [math: h=15m] h = 15 \, \text{m} [math: Hx=50kN] H_x = 50 \, \text{kN} [math: Hy=405.36kN] H_y = 405.36 \, \text{kN} [math: Oy=294.64kN] O_y = 294.64 \, \text{kN} [math: P1=P5=P6=P7=75kN] P_1 = P_5 = P_6 = P_7 = 75 \, \text{kN} [math: P2=P3=135kN] P_2 = P_3 = 135 \, \text{kN} [math: P4=158.11kN] P_4 = 158.11 \, \text{kN} Determine the forces in members DE, LE and LM. Force in member ([math: DE] ) = Answer 6[input] kN (2 marks) Force in member ([math: LE] ) = Answer 7[input] kN (2 marks) Force in member ([math: LM] ) = Answer 8[input] kN (2 marks) Notes Report question issue Question 3 Notes

Question text 13Marks Problem 3Consider the truss in Figure P3, which is supported on a pin at point A and a rocker/roller at point G. It is loaded with three horizontal forces [math: P=600] kN, [math: Q=200] kN, and [math: R=500] kN, and a vertical force [math: S=250] kN. The support reaction forces and their assumed directions are illustrated in the figure and their values are [math: Ax=−1300]A_x=-1300 kN, [math: Ay=−7500]A_y=-7500 kN, and [math: Gy=7750]G_y=7750 kN. Here, [math: H=3] m. Figure P3. Truss loaded with various point forces.a) Determine the number of zero-force members in the truss. [1 mark]Number of zero-force members = Answer 1[input]b) Determine the force in member DE. Use a positive value to indicate tension and a negative value to indicate compression. Provide your answer in kN to 4 decimal places. [2 marks]Force in member DE [kN] = Answer 2[input]c) Determine the force in member DC. Use a positive value to indicate tension and a negative value to indicate compression. Provide your answer in kN to 4 decimal places. [2 marks]Force in member DC [kN] = Answer 3[input]d) Determine the force in member BC. Use a positive value to indicate tension and a negative value to indicate compression. Provide your answer in kN to 4 decimal places. [2 marks]Force in member BC [kN] = Answer 4[input]e) Determine the force in member FE. Use a positive value to indicate tension and a negative value to indicate compression. Provide your answer in kN to 4 decimal places. [2 marks]Force in member FE [kN] = Answer 5[input]f) Determine the force in member BE. Use a positive value to indicate tension and a negative value to indicate compression. Provide your answer in kN to 4 decimal places. [2 marks]Force in member BE [kN] = Answer 6[input]g) Consider the case where the vertical load, S, is able to change. All other loads (P, Q, and R) remain the same. Determine the maximum allowable magnitude of S if support G can only manage a force magnitude of 20,000 kN. Provide your answer in kN to 4 decimal places. [2 marks]Maximum allowable magnitude of S [kN] = Answer 7[input]Notes Report question issue Question 3 Notes

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