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Part 1Evaluate the following integral in cylindrical coordinates.ModifyingAbove ModifyingBelow Integral from nothing to nothing With 2 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With 3 StartRoot 2 EndRoot divided by 2 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With StartRoot 9 minus x squared EndRoot width x e Superscript negative x squared minus y squared Baseline dy font size decreased by 4 dx font size decreased by 4 dz2∫ 032/2∫0 9−x2∫xe−x2−y2dy dx dz Part 1ModifyingAbove ModifyingBelow Integral from nothing to nothing With 2 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With 3 StartRoot 2 EndRoot divided by 2 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With StartRoot 9 minus x squared EndRoot width x e Superscript negative x squared minus y squared Baseline dy font size decreased by 4 dx font size decreased by 4 dz2∫ 032/2∫0 9−x2∫xe−x2−y2dy dx dzequals=[input]negative \frac StartSet 3−\frac{3 (Type an exact answer, using piπ as needed.)
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思路分析
The problem statement provided is a bit garbled and does not include multiple-choice options to analyze. I will first acknowledge what is given and then outline a clear approach to evaluating the integral, highlighting how one would confirm or derive the provided exact answer.
What is given or implied:
- An integral written in cylindrical coordinates appears, involving an integrand with x e^{-(x^2+y^2)} and some bounds that are difficult to parse from the text. The final displayed answer suggests an exact form involving π and e^{-9}, namely -(π/4) e^{-9} + (π/4) = (π/4)(1 - e^{-9}).
- The answer_options field is empty, which means there are no distinct MC choices to evaluate for correctness or incorrectness, so we cannot perform option-by-option reasoning in the usual sense.
Since there are no alternatives to compare against, here is a structured, step-by-step plan you would use to evaluate such an integral and verify the given exact result, along with notes on common pitfalls that could lead to confusion if the region bounds are misinterpreted.
1) Clarify the region an......Login to view full explanation登录即可查看完整答案
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Part 1Evaluate the following integral in cylindrical coordinates.ModifyingAbove ModifyingBelow Integral from nothing to nothing With 5 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With StartRoot 25 minus x squared EndRoot width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With StartRoot x squared plus y squared EndRoot width 0 left parenthesis x squared plus y squared right parenthesis Superscript negative 1 divided by 2 Baseline dz font size decreased by 4 dy font size decreased by 4 dx5∫ 025−x2∫0 x2+y2∫0x2+y2−1/2 dz dy dx Part 1ModifyingAbove ModifyingBelow Integral from nothing to nothing With 5 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With StartRoot 25 minus x squared EndRoot width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With StartRoot x squared plus y squared EndRoot width 0 left parenthesis x squared plus y squared right parenthesis Superscript negative 1 divided by 2 Baseline dz font size decreased by 4 dy font size decreased by 4 dx5∫ 025−x2∫0 x2+y2∫0x2+y2−1/2 dz dy dxequals=[input]enter your response here (Type an exact answer, using piπ as needed.)
Part 1Evaluate the following integral in cylindrical coordinates.ModifyingAbove ModifyingBelow Integral from nothing to nothing With 2 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With 3 StartRoot 2 EndRoot divided by 2 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With StartRoot 9 minus x squared EndRoot width x e Superscript negative x squared minus y squared Baseline dy font size decreased by 4 dx font size decreased by 4 dz2∫ 032/2∫0 9−x2∫xe−x2−y2dy dx dz Part 1ModifyingAbove ModifyingBelow Integral from nothing to nothing With 2 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With 3 StartRoot 2 EndRoot divided by 2 width 0 ModifyingAbove ModifyingBelow Integral from nothing to nothing With StartRoot 9 minus x squared EndRoot width x e Superscript negative x squared minus y squared Baseline dy font size decreased by 4 dx font size decreased by 4 dz2∫ 032/2∫0 9−x2∫xe−x2−y2dy dx dzequals=[input]enter your response here (Type an exact answer, using piπ as needed.)
Part 1[table] Use a triple integral to find the volume of the solid bounded by the surfaces zequals=2e Superscript yey and zequals=22 over the rectangle StartSet left parenthesis x,y right parenthesis : 0 less than or equals x less than or equals 1, 0 less than or equals y less than or equals ln 4 EndSet{(x,y): 0≤x≤1, 0≤y≤ln4}. | ln 4ln411xxyyzz [/table] Part 1The volume of the solid is [input]enter your response here [input] ▼ units. cubic units. square units. empty selection (Type an exact answer.)
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