The non-coding strand of a region of double-stranded DNA has the sequence 5′-TCAGTGAGTATACATGGC-3′.Assuming standard initiation of translation, what is the corresponding polypeptide that would be encoded by the coding strand?Type in your answer below using the single amino acid code.[Do not type any additional characters. For example, if your answer is “PEPTIDE” followed by a stop codon, simply type in: PEPTIDE]

Question

BlackTom AI · Accepted Answer

The question provides the non-coding (template) strand sequence in the 5' to 3' direction: 5'-TCAGTGAGTATACATGGC-3'. To determine the encoded polypeptide, we can follow these steps:

- First, identify the coding strand by computing the reverse complement of the non-coding strand. Complementing T with A, C with G, A with T, and G with C gives the intermediate complement strand in the 3' to 5' direction. Reversing this result yields the coding strand in the 5' to 3' orientation.
- The reverse complement (coding strand) in 5' to 3' is: GCCATGTATACTCACTGA.
- Next, convert this coding strand into the mRNA sequence by replacing each T with U (since transcription produces an RNA strand with uracil). The resulting mRNA sequence is: GCCAUGUAUACUCA CUGA -> specifically GCCAUGUAUACUCA CUGA, which translates to codons as follows: GCC | AUG | UAU | ACU | CAC | UGA.
- Now translate codons into amino acids using the standard genetic code:
  - GCC encodes Alanine (A)
  - AUG encodes Methionine (M) and also serves as the start codon
  - UAU encodes Tyrosine (Y)
  - ACU encodes Threonine (T)
  - CAC encodes Histidine (H)
  - UGA is a stop codon, terminating translation
- Therefore, the polypeptide sequence produced before termination is: Alanine – Methionine – Tyrosine – Threonine – Histidine, abbreviated in one-letter codes as AMYTH.

Consider the provided answer of MY. This would correspond to a peptide comprising only Methionine and Tyrosine, which would ignore the remaining codons in this reading frame (Ala, Thr, and His) and would imply an incomplete translation with an early stop that is not supported by the given sequence. The presence of a valid start codon (AUG) and the subsequent codons in the same frame clearly yields AMYTH before encountering the stop codon UGA.

In summary, the encoded polypeptide, following standard initiation of translation and reading frame from the identified start codon, is AMYTH; the answer MY does not account for the full coding sequence and therefore is incorrect.

查看解析

登录即可查看完整答案

类似问题

Question at position 18 A sequence of eukaryotic mRNA that reads: 5'-GpppCCUGUGGACAUGCCUGAAUCAGCUUUAAUCUGAAAAAAA-3' should code for ____ amino acids after all steps of conversion into protein are complete.7101168Clear my selection

Question at position 22 What does a ribosome read during translation?mRNAtemplate strand of DNAcoding strand of DNA

Question at position 25 A sequence of eukaryotic mRNA that reads: 5'-GpppCCUGUGGACAUGCCUGAAUCAGCUUUAAUCUGAAAAAAA-3' should code for ____ amino acids after all steps of conversion into protein are complete.6781110Clear my selection

_______ is the process in which a protein is assembled at a ribosome.

The bottom loop of the tRNA molecule is called the . This sequence recognizes and pairs with the on the mRNA.

What process converts the mRNA "message" into a sequence of amino acids?

更多留学生实用工具

考试浏览器助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单