An aluminum plate has a circular hole. If the temperature of the plate increases, what happens to the size of the hole?

Question

BlackTom AI · Accepted Answer

When a solid like aluminum is heated, it undergoes thermal expansion. For most materials, this expansion is approximately isotropic, meaning it occurs uniformly in all directions.

Option 1: Increases. This is the correct general behavior: as the plate expands, the hole size increases along with the surrounding material because the material around the hole expands outward. The circular boundary grows in all directions, so the diameter of the hole becomes larger.

Option 2: Decreases. This would imply contraction upon heating, which contradicts the basic property of positive coefficients of thermal expansion for aluminum.

Option 3: Increases the top half of the hole. Thermal expansion acts uniformly in all directions; there’s no mechanism that would cause only the top half to grow more than the bottom half.

Option 4: Stays the same. If the plate heats up but the hole size remains unchanged, that would violate the principle that materials expand with temperature (unless there were compensating constraints or anisotropic effects, which are not described here).

In summary, the hole enlarges because the surrounding aluminum expands upon heating, causing the boundary of the hole to move outward in every direction.

SPHY001 Practice Quiz - Unit 13 | LA053

An aluminum plate has a circular hole. If the temperature of the plate increases, what happens to the size of the hole?

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