Question2 What is the output after running the code below: print('\//' * 2)Select one alternative: \//\// \//\/\ //// TypeError ResetMaximum marks: 2 Flag question undefined

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BlackTom AI · Accepted Answer

The question asks what output results from print('\//' * 2).

First, decode the string literal: '\\//' in Python represents two backslash characters followed by two forward slashes. This is because each pair of backslashes in a normal string escapes to a single backslash, so '\' becomes '\' (two backslashes as characters), and then the '//' remain as two forward slashes. Therefore the string value is: \ (backslash), \ (backslash), /, /.

Next, multiplying that string by 2 repeats the entire sequence twice: '\//' * 2 becomes '\//\//'. When printed, Python shows the backslashes as literal backslash characters and the slashes as forward slashes, yielding the sequence: two backslashes, two forward slashes, two backslashes, two forward slashes — i.e., exactly two backslashes followed by two forward slashes, repeated twice.

Now evaluate each option:
- Option 1: "\//\//
" — This shows two backslashes, two forward slashes, repeated twice, and then a newline. The content matches the evaluated string; the trailing newline is consistent with print adding a newline. This option aligns with the actual result.
- Option 2: "\\/\/\n" — Here the escaping is inconsistent with the actual repetition; the sequence shown does not correspond to two backslashes followed by two forward slashes twice. It misrepresents the number and placement of backslashes and slashes, so it is incorrect.
- Option 3: "//\//
" — This begins with forward slashes, dropping the leading backslashes entirely, which does not reflect the original string or its repetition. It is not a correct representation of the output.
- Option 4: "TypeError" — This would only occur if there were a runtime error, which is not the case for this simple string multiplication and print operation, so this option is incorrect.

In summary, the first option correctly represents the literal content produced by the expression, including the exact sequence and the trailing newline added by print. The other options differ in the escaping, ordering, or presence of characters, or presume an error that does not occur here.

Question2 What is the output after running the code below: print('\\//' * 2)Select one alternative: \\//\\// \\\//\\/\\ \//\// TypeError ResetMaximum marks: 2 Flag question undefined

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