Review the code snippet below:
name1 = "Betty joe"
name2 = "Betty Jean"
name3 = "Betty Jane"
if name1

Question

Review the code snippet below:
name1 = "Betty joe"
name2 = "Betty Jean"
name3 = "Betty Jane"
if name1 < name2 :
   if name1 < name3 :
       print(name1, "is first")
   else :
       print(name3, "is first")
else :
   if name2 < name3 :
      print(name2, "is first")
   else :
      print(name3, "is first") 
what output is produced?

BlackTom AI · Accepted Answer

First, let's restate what the code is doing in plain terms and then test each option.
Option 1: "Betty joe is first". This would be printed if the first if-condition evaluated to true and the inner condition also pointed to name1 as the smallest. However, comparing the strings lexicographically reveals that name1 ("Betty joe") is not less than name2 ("Betty Jean"); also, the nested check would then compare name1 with name3, which does not lead to name1 being declared first. Therefore, this option does not match the actual execution.
Option 2: "Betty Jane is first". To see why this is the result, follow the logic: name1 < name2 evaluates to False because of the mixed-case letters after "Betty "; specifically, 'j' (lowercase) comes after 'J' (uppercase) in ASCII, so name1 is not less than name2. Consequently, we go to the else branch and check name2 < name3. Here, "Betty Jean" is also not less than "Betty Jane" since after the shared prefix "Betty J", 'e' comes before 'a' in the two strings, making "Betty Jean" > "Betty Jane". Therefore, the else clause of the outer if executes, printing name3 with "is first", which yields "Betty Jane is first".
Option 3: "Betty joe is firstBetty Jean is firstBetty Jane is first". This option looks like a concatenation of multiple prints without spacing, which would only occur if multiple print statements were executed back-to-back. The given code prints exactly one phrase, so this composite string cannot be produced by the program.
Option 4: "Betty Jean is first". This would require name2 to be the smallest among the three names, but as shown, name2 is not less than name3, and name1 is not less than name2 either. Hence, this option does not align with the actual control flow and the resulting print.
In summary, the actual program flow selects name3 as first due to the failed initial comparison and the subsequent failed second comparison, leading to printing "Betty Jane is first". The only option that matches this outcome is the second choice.

Spr25_CS003C_37772 Ch. 3 Practice Quiz

Review the code snippet below: name1 = "Betty joe" name2 = "Betty Jean" name3 = "Betty Jane" if name1 < name2 : if name1 < name3 : print(name1, "is first") else : print(name3, "is first") else : if name2 < name3 : print(name2, "is first") else : print(name3, "is first") what output is produced?

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