题目
题目

COMM_V 205 101 102 103 2025W1 Breakout Group (BG) 8

多项选择题

Exception in Logical Comparison with string data (Continuing): Logical comparisons of string data in R are performed based on alphabetical ordering, ignoring letter case at first. However, when two strings are identical apart from case, R uses case to break the tie—uppercase letters are considered greater than their lowercase counterparts (i.e., "A" > "a"). R compares the strings character by character from the beginning until it can determine which one is greater. For example: "uBc" and "ubc" are identical if case is ignored. R therefore compares them character by character: The first characters, "u" and "u", are both lowercase—no difference. The second characters, "B" and "b", differ in case. Since "B" is uppercase, it is considered greater than lowercase "b". Thus, R stops comparing further characters and concludes that "uBc" > "ubc". Which of the following comparisons result in TRUE?

选项
A."Apple">"apple"
B."aPple"<"Apple"
C."applE">"apple"
D."APple">"ApPLE"
查看解析

查看解析

标准答案
Please login to view
思路分析
To determine which of the given string comparisons are TRUE under R's rules, we must follow the described comparison process: compare character by character, using case-insensitive comparison first, and only when strings are identical except for case do we apply the case-based tie-breaker where uppercase is considered greater than lowercase. Option 1: "Apple">"apple" - Compare ignoring case: both strings are the same sequence of letters, so the comparison is a tie up to the entire string. - App......Login to view full explanation

登录即可查看完整答案

我们收录了全球超50000道考试原题与详细解析,现在登录,立即获得答案。

类似问题

Question at position 7  What is the value of the variable Flag at the end of the following lines of code: Flag = 1Flag = 0Code will not run. Error!Flag is the ASCII equivalent of the word 'Toney'

Consider the following code segment: s1 = "CAT"s2 = "cat"Which of the following if statements has a condition that evaluates to True?

Review the code snippet below: name1 = "Betty joe"name2 = "Betty Jean"name3 = "Betty Jane"if name1 < name2 : if name1 < name3 : print(name1, "is first") else : print(name3, "is first")else : if name2 < name3 : print(name2, "is first") else : print(name3, "is first") what output is produced?

Consider the following code segment: s1 = "CAT" s2 = "cat" Which of the following if statements has a condition that evaluates to True?

更多留学生实用工具

加入我们，立即解锁 海量真题 与 独家解析，让复习快人一步！