题目
题目

MCD4400 - T3 - 2025 Prelab Quiz - Esterification - Benzocaine

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Question textBelow is the reaction you will be performing today: To perform the synthesis you will be using the following reagents: [table] p-aminobenzoic acid (PABA) | ethanol M = 137.14 g mol-1 | M = 47.07 g mol-1 0.80 g | 10 mL (density: 0.789 g mL-1) [/table] Calculate (to 2 significant figures): No. of moles of PABA: Answer 1 Question 4[input] mol Mass of ethanol: Answer 2 Question 4[input] grams No. of moles of ethanol: Answer 3 Question 4[input] mol Determine the molar ratio of PABA : ethanol being used today (round to the nearest integer): [table] PABA | : | ethanol Ratio = nPABA / nPABA | | Ratio = nethanol / nPABA Ratio =  1 | : | Answer 4 Question 4 [/table] Out of PABA and ethanol, which reagent will be used in excess? Multiple choice 1 Question 41. PABA2. Ethanol3. Neither is in excess – they will be used in their stoichiometric ratios

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We start by extracting the given data and calculating step by step. - PABA mass = 0.80 g; M(PABA) = 137.14 g/mol. Number of moles of PABA = 0.80 g ÷ 137.14 g/mol ≈ 0.00583 mol. Rounding to two significant figures gives 0.0058 mol. - Ethanol volume = 10 mL; density = 0.789 g/mL. Mass of ethanol = 10 mL × 0.789 g/mL = 7.89 g. Rounding ......Login to view full explanation

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