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Question textBelow is the reaction you will be performing in the coming schedule week: To perform the synthesis you will be using the following reagents: [table] p-aminobenzoic acid (PABA) | ethanol M = 137.14 g mol-1 | M = 47.07 g mol-1 0.80 g | 10 mL (density: 0.789 g mL-1) [/table] Calculate (to 2 significant figures): No. of moles of PABA: Answer 1 Question 4[input] mol Mass of ethanol: Answer 2 Question 4[input] grams No. of moles of ethanol: Answer 3 Question 4[input] mol Determine the molar ratio of PABA : ethanol (round to the nearest integer): [table] PABA | : | ethanol Ratio = nPABA / nPABA | | Ratio = nethanol / nPABA Ratio =  1 | : | Answer 4 Question 4 [/table] Out of PABA and ethanol, which reagent will be used in excess? Multiple choice 1 Question 41. PABA2. Ethanol3. Neither is in excess – they will be used in their stoichiometric ratiosMark 1.00 out of 1.00

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We start by identifying the given quantities and molar masses: PABA has M = 137.14 g/mol and mass = 0.80 g; ethanol has M = 47.07 g/mol (per the table) and volume = 10 mL with density 0.789 g/mL. Step 1 — Number of moles of PABA: moles = mass / M = 0.80 g / 137.14 g/mol ≈ 0.00583 mol. Rounding to 2 significant figures gives 0.0058 mol. Step ......Login to view full explanation

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