What will this code print?

Question

BlackTom AI · Accepted Answer

Let’s walk through what the code does step by step and what gets printed.

- Start with stack = []: an empty list is created.
- stack.append("A"): the string "A" is added to the end of the list, so stack becomes ["A"].
- stack.append("B"): the string "B" is added, so stack becomes ["A", "B"].
- stack.pop(): this removes the last element from the list, which is "B", leaving ["A"].
- print(stack): this prints the current contents of the list, which is ['A'].

Now evaluating the answer options:
- Option 1: [‘A’, ‘B’] — This would be the list if no pops occurred; it’s incorrect because we removed 'B'.
- Option 2: [‘A’] — This matches the resulting list ["A"] after the pop operation. The exact representation in Python uses single quotes around A, so the intended option shows A in brackets with quotes.
- Option 3: ['B'] — This would be the list if only A were removed, leaving B; that’s not what happened.
- Option 4: Error — There is no error in the code; it runs and prints the list.
- Option 5: [] — This would be the empty list if every element were popped, which is not the case here.

In summary, after pushing A and B and then popping, the list contains only A, so the printed output is ['A'].

What will this code print?

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