题目
单项选择题
Stacks_P_6 Consider an ArrayStack instance that undergoes the following operations: After all the operations above have been performed in order, answer the following: Part 1: What is the final state of the stack (from bottom of the stack to top)?Part 2: What value would be returned by the last pop() operation shown above?
选项
A.Part1: The stack is now ['apple', 'banana', 'date'], and
Part2: the last pop() will return 'date'.
B.Part1: The stack is now ['apple', 'banana', 'date'], and
Part2: the last pop() will return 'cherry'.
C.Part1: The stack is now ['apple', 'banana'], and
Part2: the last pop() will return 'cherry'.
D.Part1: The stack is now ['apple', 'cherry', 'date'],and
Part2: the last pop() will return 'banana'.
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思路分析
We start by restating the given problem to ensure we understand what is being asked and what the possible outcomes are. The prompt describes an ArrayStack instance that undergoes a sequence of operations (not shown here), and asks two things after all operations: Part 1 the final state of the stack from bottom to top, and Part 2 the value returned by the last pop() operation. The answer options present different final stack contents and corresponding last popped values. Now let’s evaluate each option in turn, considering what a typical ArrayStack behavior would produce after a sequence of push and pop operations, and paying close attention to order and which elements remain or are removed.
Option 1: Part1: The stack is now ['apple', 'banana', 'date'], and
Part2: the last pop() will return 'date'.
This option claims that, from bottom to top, the stack reads apple, then banana, then date. It also asserts that the last pop() yields date, implying date is the top element just before the final pop. If this were true, then date would have remained on top at the end of the sequence, and the final pop would remove date, leaving ['apple', 'bana......Login to view full explanation登录即可查看完整答案
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