How can you describe the specific heat of olive oil if it takes approximately 420 J of heat to raise the temperature of 7 g of olive oil by 30C?

Question

BlackTom AI · Accepted Answer

To evaluate the specific heat, start by recalling the formula q = m c ΔT, where q is heat, m is mass, c is specific heat, and ΔT is temperature change.

First, compute the mass in kilograms: 7 g = 0.007 kg.
Next, determine the temperature change: ΔT = 30°C.
Then solve for c: c = q / (m ΔT) = 420 J / (0.007 kg × 30°C) = 420 / 0.21 ≈ 2000 J/(kg·K).
Now compare to the known specific heat of water, which is about 4184 J/(kg·K).
Since olive oil’s calculated c ≈ 2000 J/(kg·K) is noticeably smaller than water’s 4184 J/(kg·K), olive oil has a lower specific heat than water.

Option-by-option analysis:
- greater than the specific heat of water: This would require c to be > 4184 J/(kg·K), which our calculation shows is not the case. Therefore this is incorrect.
- less than the specific heat of water: This aligns with c ≈ 2000 J/(kg·K) being below 4184 J/(kg·K). This is consistent with the data and the calculation. Hence this is correct.
- equal to the specific heat of water: Equality would demand c ≈ 4184 J/(kg·K), which contradicts the computed 2000 J/(kg·K). This is incorrect.
- Not enough information is given.: The provided values for q, m, and ΔT suffice to compute c, so this option is incorrect.

In summary, the derived specific heat for the olive oil is about 2000 J/(kg·K), which is less than that of water, supporting the selected option.

Chemistry (H) - Varnold - Preparatory Academy - 2nd Semester - 2024/2025 2025 Thermochemistry Practice Test

How can you describe the specific heat of olive oil if it takes approximately 420 J of heat to raise the temperature of 7 g of olive oil by 30C?

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