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题目
题目
单项选择题

A light ray passes from water (refractive index ( n1 = 1.33 )) into diamond (refractive index ( n2 = 2.42 )). If the angle of incidence in water is ( 300 ), what is the angle of refraction in diamond?

选项
A.a. 19.20
B.b. 22.80
C.c. 15.50
D.d. 25.40
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标准答案
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思路分析
We start from Snell's law for refraction: n1 sin(theta1) = n2 sin(theta2). Given: n1 = 1.33, theta1 = 30 degrees, n2 = 2.42. Compute sin(theta2): sin(theta2) = (n1 * sin(theta1)) / n2. sin(30°) = 0.5, so sin(theta2) = (1.33 * 0.5) / 2.42 = 0.665 / 2.42 ≈ 0.2748. Now find theta2: theta2 ≈ arcsin(0.2748) ≈ 15.9 degrees. This is the ......Login to view full explanation

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Which of the following statements best describes Snell's Law and its application in determining the path of light as it passes from one medium to another?

A light ray in glass arrives at the glass-water interface at an angle of θ = 48° with the normal. The refracted ray in water makes an angle φ = 72° with the normal, as shown in the figure. The index of refraction of water is 1.33. The angle of incidence is now changed to θ = 37°. What is the new angle of refraction φ in the water? Hint: Start by calculating the index of refraction of the glass. 

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