An SHM system is oscillating with angular frequency w = 5.6 rad s-1 and amplitude a = 0.12 m. Calculate the maximum value of the velocity of the oscillator, in m s-1 , to 3 s.f.

Question

BlackTom AI · Accepted Answer

Consider the standard result for simple harmonic motion: the maximum speed occurs at the equilibrium position and equals v_max = ωA, where ω is the angular frequency and A is the amplitude.

First, identify the given quantities: angular frequency ω = 5.6 rad s−1 and amplitude A = 0.12 m.

Next, apply the formula v_max = ωA by substituting the given values: v_max = 5.6 × 0.12.

Perform the multiplication: 5.6 × 0.12 = 0.672. This is the raw numerical result for the maximum velocity in SI units (m s−1).

Since the problem asks for 3 significant figures, round 0.672 to 3 s.f. The value 0.672 already has three significant figures, so it remains 0.672 m s−1.

Thus, the maximum speed of the oscillator, to three significant figures, is obtained by using the relationship v_max = ωA and results in the value derived from the substitution and multiplication above.

B27FF 1. Periodic Motion and Simple Harmonic Motion

An SHM system is oscillating with angular frequency w = 5.6 rad s-1 and amplitude a = 0.12 m. Calculate the maximum value of the velocity of the oscillator, in m s-1 , to 3 s.f.

查看解析

登录即可查看完整答案

类似问题

To double the period of a simple harmonic oscillator, by what factor should the amplitude change?

In the above system the spring constant is k = 25 N/m and the mass on the spring is 100 grams. What are the angular velocity and the harmonic frequency if we triple the mass? Round your answer to one (1) decimal place. Do not enter units. Example: 33.4

A mass in the diagram below undergoes simple harmonic When the mass reaches point x = 0 its instantaneous acceleration is:

A mass attached to a very light spring executes simple harmonic motion. If you want to double its total energy, you should

If the total energy of a harmonic oscillator is reduced to 1/3 of its original value, what is the change in the amplitude of the oscillations?

A mass in the diagram below undergoes simple harmonic When the mass reaches point x = 0 its instantaneous acceleration is:

A mass in the diagram below undergoes simple harmonic When the mass reaches point x = +A its instantaneous acceleration is:

A mass in the diagram below undergoes simple harmonic When the mass reaches point x = 0 its instantaneous velocity is:

更多留学生实用工具

考试浏览器助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单