题目
题目
单项选择题

When the shear force diagram passes through the zero axis, the corresponding bending moment at the same location will be...?

选项
A.a. equal to zero
B.b. above the zero axis line, i.e., negative
C.c. below the zero axis line, i.e., positive
D.d. a local maximum or minimum
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标准答案
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思路分析
Consider the relationship between the shear force diagram (SFD) and the bending moment diagram (BMD): the slope of the bending moment at any location equals the shear force at that location. With that in mind, we can evaluate each option. Option a: 'equal to zero' — This would claim that the bending moment value is zero exactly where the shear crosses zero. While it is possible for the moment to be zero at certain points, the fact that the shear force is zero does not guarantee that......Login to view full explanation

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Step 2: Shear and Moment Functions A free-body diagram of a beam segment of length x is shown. The intensity of the triangular load at the section is found by proportion, that is, w/x=(2kN/m)/(3m) or   w=( 2 3  x)  . The resultant of the distributed loading is found from the area under the diagram. Thus, \sum F_y=0=(3\,kN)-\frac{1}{2}\left(\frac{2}{3}x\right)x [ Select ] +V -V +M -M V=\left(3-\frac{1}{3}x^2\right)kN \sum M_x=0=(6kNm)-(3kN)(x)+\frac{1}{2}(2/3\,x)x(1/3\,x) [ Select ] -Vx +Vx +M -M M=(-6+3x-\frac{1}{9}x^3) kNm   Choose the missing terms in the above equations

Step 2: Shear and Moment Functions A free-body diagram of a beam segment of length x is shown. The intensity of the triangular load at the section is found by proportion, that is, w/x=(2kN/m)/(3m) or   𝑤 = ( 2 3   𝑥 )   kN / m . The resultant of the distributed loading is found from the area under the diagram. Thus, \sum F_y=0=(3\,kN)-\frac{1}{2}\left(\frac{2}{3}x\right)x [ Select ] +V -V +M -M V=\left(3-\frac{1}{3}x^2\right)kN \sum M_x=0=(6kNm)-(3kN)(x)+\frac{1}{2}(2/3\,x)x(1/3\,x) [ Select ] -Vx +Vx +M -M M=(-6+3x-\frac{1}{9}x^3) kNm   Choose the missing terms in the above equations

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