题目
CVEN90051_2025_SM2 Module #2 Practice Quiz
数值题
A river has the following hydraulic characteristics: Q = 528 m3/s, width 51 m, depth 6.4 m, bed slope S = 0.002 and Manning's n = 0.027 (the channel is NOT wide). The sediment has a typical diameter D50 = 2.5 mm, density = 2650 kg/m3 and kinematic viscosity = 10−6 m2/s. Estimate the bed load transport using the Mayer-Peter formula, assuming that no bed forms are present. (Answer in m2/s)
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思路分析
Re-state the problem clearly to set the context: a river with discharge Q = 528 m3/s, channel width 51 m, depth 6.4 m, bed slope S = 0.002, Manning n = 0.027, sediment with D50 = 2.5 mm, ρs = 2650 kg/m3, ν = 1e-6 m2/s. We are asked to estimate the bed load transport using the Mayer-Peter formula, assuming no bed forms, and to report the result in m2/s.
Step 1: Compute the bed shear stress to gauge the driving force on the bed material.
- In uniform open-channel flow, the bed shear stress can be approximated by τ = ρ g h S for a wide, rectangular channel, where h is depth and S is the bed slope.
- Given ρ ≈ 1000 kg/m3, g ≈ 9.81 m/s2, h = 6.4 m, S = 0.002:
τ = 1000 * 9.81 * 6.4 * 0.002 ≈ 158 Pa.
Step 2: Compute the non-dimensional Shields parameter θ to assess whether transport is expected and to what extent.
- The effective submerged density difference is (ρs − ρ) ≈ 1650 kg/m3.
- With D50 = 2.5 mm = 0.0025 m, θ = τ / [(ρs − ρ) g D50].
- Denominator: (ρs − ρ) g D50 ≈ 1650 * 9.81 * 0.0025 ≈ 40.5.
- Therefore θ ≈ 158 / 40.5 ≈ 3.9......Login to view full explanation登录即可查看完整答案
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