The time constant for capacitors states that

Question

BlackTom AI · Accepted Answer

Here is what we know about the time constant for capacitors and how it relates to charging or discharging behavior.

Because this item has no answer options provided, we cannot assess each choice individually. We can still reason about the typical statement regarding the time constant tau.

In an RC circuit, the capacitor voltage during charging follows v(t) = V_final(1 − e^(−t/RC)). The time constant tau = RC governs how quickly the capacitor voltage approaches its final value V_final. After about 1 tau, the voltage reaches roughly 63% of V_final. After about 2 tau, it’s around 86%, and after about 3 tau, it’s near 95%. By 4 tau, it’s about 98%, and by 5 tau, it’s approximately 99.3% of V_final.

Given that, a statement claiming that 99% of the circuit voltage is available in five time constants (five tau) is a rough approximation. It captures the general idea that most of the final voltage is reached after several time constants, but the exact figure is closer to 99.3% at 5 tau, not exactly 99%. The use of 99% is a simplification and depends on how strictly the percentage threshold is defined.

If there were multiple options, you’d evaluate them against this standard behavior: verify whether the option accurately reflects the exponential approach to the final voltage with the tau parameter, and whether percentages and time multiples (1 tau, 2 tau, etc.) align with the standard RC charging/discharging equations.

Without the listed choices, we can’t identify which option is correct or incorrect, but the core concept to test is understanding that the time constant tau determines the rate, and that reaching >99% of final voltage occurs at roughly five tau in a typical RC charging scenario. Any option that states a precise, commonly cited percentage should be checked against the exponential model (e^(−t/RC)) to confirm its accuracy.

AMT102 36396 Quiz #2 BE Practical Apps

The time constant for capacitors states that

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