Let's start with creating the following vector. my_vector = 4 & my_vector

Question

Let's start with creating the following vector.

my_vector <- c(1,2,3,4,5,6,7,8,9,10)

After creating the vector, if you execute the following code successfully in R, the output given is 4.

[ Select ]
sum
mean
median
sd
 (my_vector >= 4 & my_vector < 
[ Select ]
5
6
7
8
9
10
 )

Please complete the formula. You can only use a single-digit number, name of an aggregate statistics function (such as sum, mean, median, sd, etc.), a logical operator, or an arithmetic operator in each blank.

BlackTom AI · Accepted Answer

We start by restating the given problem to ensure clarity about what is being asked. Question setup: - A numeric vector is created: my_vector <- c(1,2,3,4,5,6,7,8,9,10). - An expression is evaluated in R with two blanks to fill in: [ Select ] sum mean median sd (my_vector >= 4 & my_vector < [ Select ] 5 6 7 8 9 10 ) - The goal is to fill the blanks so that the overall expression 결과 outputs the number 4. - Each blank must contain only a single-digit number, the name of an aggregate statistic function, a logical operator, or an arithmetic operator. Now, analyze the options for each blank separately. First blank (the function to apply to the logical condition): - If we insert sum as the function, the expression becomes sum(my_vector >= 4 & my_vector < [Select] ...). The inner logical condition (my_vector >= 4 & my_vector < X) yields a logical vector where TRUE corresponds to elements of my_vector that satisfy the condition, and FALSE otherwise. In R, when you sum a logical vector, TRUE counts as 1 and FALSE as 0. Therefore, the sum would count how many elements satisfy the condition, not sum their values. This is exactly how we can obtain the number of elements meeting the condition. - If we replaced the function with mean, median, or sd, the result would be a numeric statistic of the logical vector (e.g., mean would be the proportion of TRUEs, median would be the middle value after coercion to numeric, sd would be the spread). These would not necessarily yield 4 given the structure of the problem, so sum is the correct intent to reach 4 as a count of satisfying elements. Second blank (the upper bound in the range): - The condition is my_vector >= 4 & my_vector < [Select]. We must choose a single-digit upper bound that, when combined with 4 as the lower bound, yields exactly 4 elements in the vector satisfying the condition. The vector is 1 through 10. The elements satisfying my_vector >= 4 & my_vector < X are 4, 5, 6, ..., up to the largest value strictly less than X. - Testing possible single-digit candidates: - If X = 5, the set is {4}, count = 1. - If X = 6, the set is {4,5}, count = 2. - If X = 7, the set is {4,5,6}, count = 3. - If X = 8, the set is {4,5,6,7}, count = 4. - If X = 9, the set is {4,5,6,7,8}, count = 5. - If X = 10, the set is {4,5,6,7,8,9}, count = 6. - To achieve a count of 4 satisfying elements, the appropriate upper bound is X = 8. Putting it together: - First blank should be the function that, when applied to the logical vector, yields a count of satisfying elements. Using sum accomplishes this, since sum(TRUE, FALSE, ...) counts the number of TRUEs. - Second blank should be 8, so that the condition selects exactly four elements (4, 5, 6, 7). Therefore, the correct fillings are: - First blank: sum - Second blank: 8 Why other plausible choices fail: - If you used mean as the first blank, you would obtain a proportion of TRUEs, not a count of elements, so you would not get 4. - If you used median or sd as the first blank, you would retrieve a statistic of the logical vector that is not aligned with counting how many elements satisfy the condition. - If the upper bound were 5 (instead of 8), you would only include the single value 4, giving a count of 1, not 4; similarly, 6 or 7 would yield 2 or 3, respectively, and 9 or 10 would yield counts greater than 4. In summary, selecting sum for the first blank and 8 for the second blank yields the expression: sum(my_vector >= 4 & my_vector < 8). This evaluates to 4, since there are four TRUEs in the logical condition (for the values 4, 5, 6, and 7).

COMM_V 205 101 102 103 2025W1 In-class Exercise (ICE) 9

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