Question at position 3 Consider the code fragment below. It has a missing piece of code indicated by XXX. Which of the following options complete the print statement to output 1+2+3=. print(1, 2, 3, XXX)end="+", end="
"sep=",", end="="end=",", sep="+"sep="+", end="="Clear my selection

Question

Question at position 3 Consider the code fragment below. It has a missing piece of code indicated by XXX. Which of the following options complete the print statement to output 1+2+3=. print(1, 2, 3, XXX)end="+", end="
"sep=",", end="="end=",", sep="+"sep="+", end="="Clear my selection

BlackTom AI · Accepted Answer

We need to determine which combination of print parameters will produce the literal output 1+2+3= from the call print(1, 2, 3, XXX).
Option 1: end="+", end="
". This attempts to set the end parameter twice (first to "+", then to "
"). In Python, you can only specify end once; the second specification would override the first, but this would not yield the desired 1+2+3= output and would instead end with a newline, producing something like 1 2 3+
 depending on how the other parameters behave. Moreover, the default separator would be a space unless overridden, so this option is inconsistent with the requirement to place plus signs between the numbers.
Option 2: sep=",", end="=". Here, the numbers 1, 2, 3 would be joined with the comma separator, giving 1,2,3, and then the end parameter would append =, resulting in 1,2,3=. This does not place plus signs between the numbers, so it does not produce 1+2+3=, making it incorrect.
Option 3: end=",", sep="+". With sep="+" the numbers would be joined as 1+2+3, which is good for the pluses between numbers, but end="," would append a comma at the end, yielding 1+2+3,, not 1+2+3=. The trailing comma makes this option invalid for the target output.
Option 4: sep="+", end="=". This combination ensures the elements 1, 2, 3 are joined by plus signs, giving 1+2+3, and then the end parameter appends =, producing exactly 1+2+3= as the final output. There is no conflicting parameter, and the desired characters appear in the correct order.

Question at position 3 Consider the code fragment below. It has a missing piece of code indicated by XXX. Which of the following options complete the print statement to output 1+2+3=. print(1, 2, 3, XXX)end="+", end="\n"sep=",", end="="end=",", sep="+"sep="+", end="="Clear my selection

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