A bag contains 5 red marbles and 3 blue marbles. If one marble is drawn at random, what is the probability that it is red?

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BlackTom AI · Accepted Answer

Consider the setup: a bag with 5 red and 3 blue marbles, totaling 8 marbles.
Option 1: 1/2. This would imply 4 red marbles out of 8, but there are 5 red marbles, so this undercounts the red outcomes. Therefore this is incorrect.
Option 2: 3/5. This equals 0.6, which would correspond to 4.8 red marbles out of 8 in expectation, which isn't possible; more concretely, 3/5 would require 4.8 red successes in 8 trials, which is not our discrete count. Hence this is incorrect.
Option 3: 5/8. This matches the actual probability: there are 5 favorable red outcomes out of 8 equally likely total outcomes. Therefore this is the correct probability.
Option 4: 1/3. This would imply about 2.666 red marbles out of 8, which contradicts the discrete count of red marbles present. Thus this option is incorrect.
In summary, the probability of drawing a red marble is the number of red marbles divided by the total number of marbles, i.e., 5 red out of 8 total, giving 5/8.

STP420 - Probability and Statistics Pre-Test STP420 - Probability and Statistics Pre-Test

A bag contains 5 red marbles and 3 blue marbles. If one marble is drawn at random, what is the probability that it is red?

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