What is the percentage composition by mass of sulfur in silver thiosulfate (Ag2S2O3)?

Question

BlackTom AI · Accepted Answer

The task asks for the percentage composition by mass of sulfur in the compound silver thiosulfate, with the formula Ag2S2O3.

First, determine the molar mass of Ag2S2O3. The atomic masses to use are approximately: Ag = 107.87, S = 32.06, O = 16.00. The formula contains 2 silver atoms, 2 sulfur atoms, and 3 oxygen atoms.

Molar mass = 2(107.87) + 2(32.06) + 3(16.00) = 215.74 + 64.12 + 48.00 = 327.86 g/mol.

Next, find the total mass contributed by sulfur. There are 2 sulfur atoms, so mass from sulfur = 2 × 32.06 = 64.12 g.

The percentage composition by mass of sulfur is therefore (mass of sulfur / molar mass of compound) × 100 = (64.12 / 327.86) × 100 ≈ 19.56%.

Rounding to three significant figures gives 19.6%.

In summary, sulfur contributes about 19.6% of the mass of Ag2S2O3. This calculation hinges on correct molar masses and the stoichiometric counts of each element in the formula, with sulfur mass taken from the two sulfur atoms and the total molar mass from the entire formula unit.

What is the percentage composition by mass of sulfur in silver thiosulfate (Ag2S2O3)?

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