题目
MATH1062/1005/1023 (ND) MATH1062/1023 Calculus Quiz 10
单项选择题
Consider the function 𝑓 ( 𝑥 , 𝑦 ) = sin ( 5 𝑥 𝑦 ) . What is 𝑓 𝑦 𝑥 ?
选项
A.25
𝑦
3
sin
(
5
𝑥
𝑦
)
B.−
25
𝑥
𝑦
4
sin
(
5
𝑥
𝑦
)
C.25
𝑥
𝑦
3
sin
(
5
𝑥
𝑦
)
−
25
𝑦
2
cos
(
5
𝑥
𝑦
)
D.25
𝑦
2
sin
(
5
𝑥
𝑦
)
−
25
𝑥
𝑦
3
cos
(
5
𝑥
𝑦
)
查看解析
标准答案
Please login to view
思路分析
We start by restating the problem: given f(x,y) = sin(5xy), determine the mixed partial derivative f_yx, i.e., the derivative first with respect to y and then with respect to x.
Option 1: 25 y^3 sin(5xy). This expression involves only a sine factor with a cubic power of y and lacks any cosine term or a product with x; it does not match the structure of a derivative of sin(5xy) with respect to y and then x. The original function depends on xy inside the sine, so derivatives typically bring down cosine or sine factors multiplied by powers of x or y; this option is missing those essential components.
Option 2: −25 x y^4 sin(5xy). Here we see a sine factor sin(5xy) multiplied by a p......Login to view full explanation登录即可查看完整答案
我们收录了全球超50000道考试原题与详细解析,现在登录,立即获得答案。
类似问题
Question at position 2 If z=yx2+6yz=y\sqrt{x^2+6y}, then ∂z∂y=\frac{\partial z}{\partial y\:}= yx2+6y+x2+6y\frac{y}{\sqrt{x^2+6y}}+\sqrt{x^2+6y}3yx2+6y\frac{3y}{\sqrt{x^2+6y}}3yx2+6y+x2+6y\frac{3y}{\sqrt{x^2+6y}}+\sqrt{x^2+6y}(2x+6)yx2+6y\left(2x+6\right)y\sqrt{x^2+6y}x2+6y\sqrt{x^2+6y}
Question at position 1 If f(x,y,z)=x2yz2+xy2z+xyf\left(x,y,z\right)=x^2yz^2+xy^2z+xy, then fx(1, 2, 3) =36.none of the above55.50.48.
Question text 6Marks Consider the function [math: f(x,y)=x2y2+yex−1.] f(x,y) = x^2y^2 +y e^{x-1} . a) Calculate the following partial derivatives at the point [math: (1,1)]: [math: ∂f∂x=]\frac{\partial f}{\partial x}= Answer 1[input] [math: ∂f∂y=]\frac{\partial f}{\partial y}= Answer 2[input] [math: ∂2f∂x2=]\frac{\partial^2 f}{\partial x^2}= Answer 3[input] [math: ∂2f∂x∂y=]\frac{\partial^2 f}{\partial x\partial y}= Answer 4[input] [math: ∂2f∂y2=]\frac{\partial^2 f}{\partial y^2}= Answer 5[input] b) A tangent vector to the level set of [math: f] at [math: (1,1)] is [math: (1,] Answer 6[input][math: )].Notes Report question issue Question 5 Notes
Question textLet [math: f(x,y)=ey+x2]f(x,y)={e^{y+x^2}}. What is [math: ∂f∂x(0,0)+∂f∂y(0,0)]\frac{\partial f}{\partial x}(0,0) + \frac{\partial f}{\partial y}(0,0), the value of [math: ∂f∂x+∂f∂y]\frac{\partial f}{\partial x} + \frac{\partial f}{\partial y} at the point [math: (0,0)] ?[input] Check Question 67
更多留学生实用工具
希望你的学习变得更简单
加入我们,立即解锁 海量真题 与 独家解析,让复习快人一步!