Question18 What is the structure of ‘ser3‘ after executing the following Pandas code: Select one alternative: A 5.0B 7.0C 9.0 AD 5BC 7CB 9 A 1.0B 8.0C 8.0D 4.0 A NaNB 8.0C 8.0D NaN None of the above ResetMaximum marks: 3 Flag question undefined

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Question18 What is the structure of ‘ser3‘ after executing the following Pandas code: Select one alternative: A 5.0B 7.0C 9.0 AD 5BC 7CB 9  A 1.0B 8.0C 8.0D 4.0 A NaNB 8.0C 8.0D NaN None of the above ResetMaximum marks: 3 Flag question undefined

BlackTom AI · Accepted Answer

To tackle this, I’ll map out what each piece of code creates and then see how the addition behaves at each index.
Option A corresponds to the result with values at A, B, C, and D as: A 5.0, B 7.0, C 9.0. This would require ser1 and ser2 to contribute those exact numbers at those positions, which doesn’t align with the actual data given for ser1 (1, 2, 3) and ser2 (4, 5, 6).
Option B shows A D 5, B C 7, C B 9. Here the labels seem scrambled (A, D, B, C) and the numbers 5, 7, 9 don’t correspond to the sum of matching indices across ser1 and ser2. Since ser1 has no D, and ser2 has D with value 4, a sum at D would be NaN for A and D, not 5, 7, or 9.
Option C displays A 1.0, B 8.0, C 8.0, D 4.0. This implies that A would be 1.0 and D would be 4.0, which would occur if we only took ser1 values for A and ser2 values for D without summing across overlapping indices, which is not how the addition between two aligned Series works in pandas when both have missing positions. Both A and D would be NaN because one side is missing for those indices.
Option D reads A NaN, B 8.0, C 8.0, D NaN. This matches the behavior of adding two Series with overlapping indices: for B and C the values sum to 8.0 each (2+6 and 3+5), while A and D lack a counterpart in one of the Series, yielding NaN for those positions. After sorting by index, the order becomes A, B, C, D with the corresponding values NaN, 8.0, 8.0, NaN.
The final option, None of the above, would be chosen if none of the listed patterns matched the actual result. Given the above, Option D precisely reflects the correct summed values at each index after the operation and the sorted order.
In detail, the operation ser3 = ser1 + ser2 performs alignment on the index labels. For index A, ser1 has 1 but ser2 has no A, so the sum is NaN. For B, 2 + 6 = 8.0. For C, 3 + 5 = 8.0. For D, ser1 has no D, so NaN. After sort_index(inplace=True), the index order is A, B, C, D, producing the sequence: NaN, 8.0, 8.0, NaN.
Thus, Option D is the one that matches the described result, while the other options misstate the values or ordering, or incorrectly assign values to indices that don’t align with the actual addition behavior.

Question18 What is the structure of ‘ser3‘ after executing the following Pandas code: Select one alternative: A 5.0B 7.0C 9.0 AD 5BC 7CB 9 A 1.0B 8.0C 8.0D 4.0 A NaNB 8.0C 8.0D NaN None of the above ResetMaximum marks: 3 Flag question undefined

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