题目
题目
单项选择题

Which one of the following is not a one-to-one function?

选项
A.A. [math: f:R+→R,f(x)=loge(x)] f:R^+\rightarrow R, f(x)=log_e(x)
B.B. [math: f:R→R,f(x)=sin(x)] f:R \rightarrow R, f(x)=sin(x)
C.C. [math: f:R→R,f(x)=2x] f:R \rightarrow R, f(x)=2^x
D.D. [math: f:R→R,f(x)=x3] f:R \rightarrow R, f(x)=x^3
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标准答案
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思路分析
Let's restate the problem in our own words to ensure clarity: we are asked to identify which option does not describe a one-to-one (injective) function. Option A: f: R^+ → R, f(x) = log_e(x). - The natural logarithm is strictly increasing on the positive real numbers, and each distinct input x>0 gives a distinct output log(x). Therefore, this function is one-to-one. - A common misconception would be to worry about the codomain being all ......Login to view full explanation

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