题目
题目

econ_203_120255_248725 Midterm

数值题

A population mean is claimed to be 50. You wish to prove that a population mean is less than 50. You know that the population is approximately normally distributed with a variance of 22.09. Suppose that the rejection rule is given by 𝑡 𝑠 𝑡 𝑎 𝑡 ≤ − 1.96 where 𝑡 𝑠 𝑡 𝑎 𝑡 is the relevant test statistic. Further suppose that you will take a sample of 25 individuals to perform this hypothesis test. The rejection rule can be alternatively stated as 𝑥 ¯ ≤ 𝑐 , where c is a number. What is the value of c? Do not round intermediate calculations. You may round your final answer to 4 decimal places, if needed.

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思路分析
We start by restating the core setup: testing H0: μ = 50 versus the alternative μ < 50 using a one-sided rejection rule. The problem provides the rejection rule in terms of the t statistic as ts.ta ≤ −1.96, and a sample size n = 25 with population variance......Login to view full explanation

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