题目
BU.232.630.F3.SP25 sample quiz 1
单项选择题
Consider the nonlinear model yt=θ1x θ2 t +εt where the sample data (y1,x1),...,(yT,xT) are i.i.d. and E(εt|xt)=0. We know that the nonlinear least square estimator is asymptotically normal, that is √ T ( ˆ θ NL−θ0) d ⤳ N(0,A −1 0 Ω0A −1 0 ) To compute the standard errors we need to estimate Ω0, ˆ Ω 0=[ 1 T ∑ T t=1 ˆ ε 2 t x 2 ˆ θ 2 t 1 T ∑ T t=1 ˆ ε 2 t ˆ θ 1x 2 ˆ θ 2 t log(xt) 1 T ∑ T t=1 ˆ ε 2 t ˆ θ 2 1 x 2 ˆ θ 2 t log2(xt)] What is the missing entry in the matrix ˆ Ω 0?
选项
A.𝔼(
ˆ
ε
2
t
ˆ
θ
2
1
x
2
ˆ
θ
2
t
log2(xt))
B.1
T
∑
T
t=1
ˆ
ε
2
t
x
2
ˆ
θ
2
t
C.𝔼(
ˆ
ε
2
t
x
2
ˆ
θ
2
t
)
D.1
T
∑
T
t=1
ˆ
ε
2
t
ˆ
θ
2
1
x
2
ˆ
θ
2
t
log2(xt)
E.1
T
∑
T
t=1
ˆ
ε
2
t
ˆ
θ
1x
2
ˆ
θ
2
t
log(xt)
F.𝔼(
ˆ
ε
2
t
ˆ
θ
1x
2
ˆ
θ
2
t
log(xt))
查看解析
标准答案
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思路分析
We start by restating the core components of the problem to ground the discussion. The model is nonlinear: y_t = f(x_t, θ) + ε_t, with E(ε_t | x_t) = 0. The asymptotic covariance Ω0 appears in the sandwich form A^{-1} Ω0 A^{-1}, and the consistent estimator ̅Ω0hat is built by replacing population moments with sample analogs. Specifically, Ω0 is the expectation of the outer product of the score (the gradient of the mean function with respect to θ) weighted by ε_t^2, i.e., it involves terms like ε_t^2 times components of ∂f/∂θ. When forming the plug-in estimator, we replace ε_t by its residual ε̂_t and x_t (and any transformed variables like log x_t) by their observed values, and we assemble the appropriate outer-product structure across θ components. With this in mind, let’s analyze each option one by one.
Option 1: 𝔼(ε̂_t^2 ́θ̂_2 1 x^2 θ̂_2^t log^2(x_t))
- Why this might be tempting: it places ε̂_t^2 in front and includes log(x_t) terms, which often arise from derivatives with respect to θ2 in models featuring exponentiation or log-terms. The presence of log^2(x_t) could reflect a second-order term or a squared derivative component.
- Why it’s likely incorrect: Ω0 is a population second-moment-type object that lives inside a sample-average expression for the estimator rather than a pure expectation with respect to ε̂_t^2 and transformed x_t. In the plug-in estimator, we typically replace the expectation by the empirical average 1/T ∑, not an expectation outside the sum, and we form the product of residual-squared terms with the corresponding derivatives across θ. The appearance of log^2(x_t) inside an expectation, rather than as part of the empirical sum of ε̂_t^2 times a derivative term, signals a mismatch with the standard structure of Ω0 hat for a nonlinear least squares setting.......Login to view full explanation登录即可查看完整答案
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类似问题
Consider the nonlinear model yt=θ1x θ2 t +εt where the sample data (y1,x1),...,(yT,xT) are i.i.d. and E(εt|xt)=0. We know that the nonlinear least square estimator is asymptotically normal, that is √ T ( ˆ θ NL−θ0) d ⤳ N(0,A −1 0 Ω0A −1 0 ) To compute the standard errors we need to estimate A0, ˆ A 0=[ 1 T ∑ T t=1 x 2 ˆ θ 2 t 1 T ∑ T t=1 ˆ θ 1x 2 ˆ θ 2 t log(xt) 1 T ∑ T t=1 ˆ θ 2 1 x 2 ˆ θ 2 t log2(xt)] What is the missing entry in the matrix ˆ A 0?
Consider the nonlinear model yt=θ1x θ2 t +εt where the sample data (y1,x1),...,(yT,xT) are i.i.d. and E(εt|xt)=0. We know that the nonlinear least square estimator is asymptotically normal, that is √ T ( ˆ θ NL−θ0) d ⤳ N(0,A −1 0 Ω0A −1 0 ) To compute the standard errors we need to estimate Ω0, ˆ Ω 0=[ 1 T ∑ T t=1 ˆ ε 2 t ˆ θ 1x 2 ˆ θ 2 t log What is the missing entry in the matrix 𝛺 ̂ 0 ?
Consider the nonlinear model yt=θ1x θ2 t +εt where the sample data (y1,x1),...,(yT,xT) are i.i.d. and E(εt|xt)=0. We know that the nonlinear least square estimator is asymptotically normal, that is √ T ( ˆ θ NL−θ0) d ⤳ N(0,A −1 0 Ω0A −1 0 ) To compute the standard errors we need to estimate A0, ˆ A 0=[ 1 T ∑ T t=1 x 2 ˆ θ 2 t 1 T ∑ T t=1 ˆ θ 1x 2 ˆ θ 2 t log(xt) 1 T ∑ T t=1 ˆ θ 1x 2 ˆ θ 2 t log(xt) ] What is the missing entry in the matrix ˆ A 0?
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