Assuming an MO diagram with orbital energies like that of O2 what is the bond order and number of unpaired electrons for the molecule NO2- ?

Question

BlackTom AI · Accepted Answer

Let's parse the problem and the options carefully using the MO picture hinted at by O2's energy ordering.
Option 1 claims a bond order of 2 with 0 unpaired electrons. This corresponds to a closed-shell, double-bonded description, which can be plausible for a nitrite-like species if the MO filling yields all electrons paired while forming a strong bond.
Option 2 states bond order 1 with 2 unpaired electrons. That would imply a significantly weaker bonding and two unpaired electrons, which contradicts the typical closed-shell nature expected for NO2− in this MO framework.
Option 3 asserts bond order 2 with 2 unpaired electrons. A true double bond with two unpaired electrons is inconsistent since a double bond tends to be associated with paired electrons in the pi-system, and having unpaired electrons would imply a triplet or diradical character that is not characteristic for the nitrite anion in this simple MO scheme.
Option 4 proposes bond order 2.5 with 1 unpaired electron. A bond order above 2 (toward 3) would require substantial antibonding occupation in a way that leaves an odd number of electrons, which clashes with the 18-electron count for NO2− under the assumed O2-like MO ordering.
Option 5 gives bond order 1.5 with 1 unpaired electron. While this is a common result for certain resonance structures of nitrite in a simplistic valence-bond view, the MO ordering analogous to O2 plus the extra electron in NO2− can lead to a different distribution in this specific context, making this option less consistent with the stated MO scheme.
In sum, when aligning with the provided MO-energy pattern and electron count for NO2−, the depiction that matches a fully paired set of electrons with a bond order of 2 is the sequence described in Option 1. The remaining options introduce either unpaired electrons where pairing would occur or place the bond order in a regime that does not align with the 18-electron, O2-like orbital filling assumed here.

Assuming an MO diagram with orbital energies like that of O2 what is the bond order and number of unpaired electrons for the molecule NO2- ?

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