The value of the C—S—O bond angle (or the angle about the S atom) is

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BlackTom AI · Accepted Answer

The question asks for the C–S–O bond angle (the angle about the S atom) in the given structure. 
Option 1: 'less than 180° but greater than 120°.' This would imply a wide angle near linearity, which is unlikely here because sulfur is bonded to three sigma groups (two C–S bonds and one S=O bond) and has lone-pair electron density that tends to compress bond angles rather than expand them. 
Option 2: '180°' suggests a perfectly linear arrangement around S, which is not consistent with the presence of three sigma bonds and a lone pair; VSEPR predicts some angular distortion, not a straight line. 
Option 3: 'less than 109.5° but greater than 90°.' This range matches the typical tetrahedral electron-pair geometry around sulfur when there are three sigma bonds and one lone pair, where lone-pair repulsion reduces the bond angles from ~109.5° but keeps them well above 90°. 
Option 4: '90°' would correspond to a perfect octahedral-like or square-planar arrangement for certain combinations, which is not appropriate for this three-bond, one-lone-pair situation around S; the angle would not be exactly 90°. 
Option 5: 'less than 120° but greater than 90°.' While this range could describe some trigonal planar contexts, the actual electron-domain geometry here is closer to tetrahedral with a lone pair, making the angle likely a bit above 90° but below 109.5°. 
In summary, the most accurate description given the three sigma bonds (two C–S and one S=O) plus one lone pair on sulfur is that the C–S–O angle is less than 109.5° but greater than 90°.

The value of the C—S—O bond angle (or the angle about the S atom) is

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