What is the molarity of 200 mL of solution in which 2.0 moles of sodium bromide is dissolved?

Question

BlackTom AI · Accepted Answer

To determine molarity, we use the formula M = n / V, where n is the number of moles and V is the volume of solution in liters.
Option A: 2.0 M would correspond to n/V = 2.0, so for a given n = 2.0 moles the volume V would need to be 1.0 L (since 2.0 moles / 1.0 L = 2.0 M). However, the problem states the volume is 200 mL, which is 0.200 L, not 1.0 L, so this option does not match the given volume.
Option B: 10 M arises from n/V = 10. With n = 2.0 moles and V = 0.200 L, the calculation is 2.0 moles / 0.200 L = 10 M. This aligns with the provided data.
Option C: 0.40 M would mean V = n / M = 2.0 moles / 0.40 M = 5.0 L. This volume is much larger than the provided 0.200 L, so this option is inconsistent with the given conditions.
Option D: 4.0 M implies V = 2.0 moles / 4.0 M = 0.50 L. Again, this does not match the stated volume of 0.200 L, making this option incorrect for the problem as given.
In summary, each choice represents a different volume that would be required to achieve that molarity with 2.0 moles, and only one of them corresponds to the actual 0.200 L volume provided in the problem. The calculation that directly uses n = 2.0 moles and V = 0.200 L yields the corresponding molarity for the given conditions.

Chemistry (H) - Varnold - Preparatory Academy - 2nd Semester - 2024/2025 2025 States of Matter and Solutions Practice Test

What is the molarity of 200 mL of solution in which 2.0 moles of sodium bromide is dissolved?

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