题目
MCD1550 / MCD2140 - T1 - 2025 TEST 2 (Week 6)
单项选择题
\(U = \left[ {\begin{array}{*{20}{c}}1&1&0\\2&3&4\end{array}} \right]\,\,\;\quad V = \left[ {\begin{array}{*{20}{c}}3\\1\end{array}} \right]\,\,\;\quad W = \left[ {\begin{array}{*{20}{c}}{0.6}&{0.5}\\{0.4}&{0.5}\end{array}} \right]\;\,\,\;X = \left[ {\begin{array}{*{20}{c}}3&5\\4&6\end{array}} \right]\quad \,\, \\ Y = \left[ {\begin{array}{*{20}{c}}1&3&2\\0&5&6\\0&0&1\end{array}} \right]\;\quad \) det (W) =
选项
A.a. –0.5
B.b. 0.5
C.c. 0.1
D.d. 0.2
E.e. not defined
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标准答案
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思路分析
We are given the 2x2 matrix W = [[0.6, 0.5], [0.4, 0.5]] and asked for det(W).
First, recall the formula for the determinant of a 2x2 matrix [[a, b], [c, d]]: det = ad − bc.
Option a: -0.5. If we plug a = 0.6, b = 0.5, c = 0.4, d ......Login to view full explanation登录即可查看完整答案
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