What is the output of the following code?for i in range(1, 6): if not i == 2: print(i)

Question

BlackTom AI · Accepted Answer

To understand what the code prints, follow the loop and the condition carefully. The loop iterates i over the values produced by range(1, 6), which yields 1, 2, 3, 4, 5 in that order, and for each i it prints i only if i is not equal to 2.

Option A: "1
3
4
5" — This matches exactly the values printed when i takes on 1, 2, 3, 4, 5 and the condition excludes 2. This is the correct behavior.

Option B: "1
2
3
4
5" — This would be the output if the condition did not exclude i == 2. Since the code says if not i == 2, 2 is skipped, so this option is incorrect.

Option C: "0
1
3
4
5" — The sequence starts at 0, but the loop starts at 1 due to range(1, 6). Therefore 0 would never be printed, making this option invalid.

Option D: "0
1
2
3
4
5" — This includes 0 and 2, neither of which appear in the actual output. The loop never yields 0, and 2 is skipped by the condition, so this is incorrect.

Option E: "0
1
3
4
5
6" — This contains 0 and 6, which are outside the produced sequence 1 through 5. It does not reflect the actual range or the conditional skip, so it is incorrect.

Programming Programming In-class Test- Part 1 Programming Programming In-class Test- Part 1

What is the output of the following code?for i in range(1, 6): if not i == 2: print(i)

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