题目
CIS-124-HYA-CRN48380 Section 13 Practice
多项填空题
At Iteration 3... What is count equal to? [Fill in the blank], What is the output printed? If nothing, leave blank. [Fill in the blank],
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标准答案
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思路分析
Let’s begin by examining what the question is asking for: two separate fill-in-the-blank fields labeled as part of a single iteration scenario. The first blank asks for a value to be assigned to count at Iteration 3, while the second blank asks what is printed as output given the surrounding code in that context.
For the first blank: count equal to 3. If the loop or iterative structure being referred to increments a counter once per iteration and starts counting from a base that leads to three iterations b......Login to view full explanation登录即可查看完整答案
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类似问题
Question at position 13 The function VelStat below is scrambled and your objective is to arrange the code in the correct order. To do this, match the line numbers to the corresponding line of code. The function VelStat accepts a vector of velocities (Velocity) as its input and produces an output vector (VelOver30) that contains only those values of velocity greater than 30. Note - This question contains distractors and you are allowed to use the same line of code more than once. Prompt 15Answer for prompt 1 5[input]Prompt 22Answer for prompt 2 2[input]Prompt 33Answer for prompt 3 3[input]Prompt 47Answer for prompt 4 7[input]Prompt 56Answer for prompt 5 6[input]Prompt 64Answer for prompt 6 4[input]Prompt 78Answer for prompt 7 8[input]Prompt 81Answer for prompt 8 1[input]Possible answersif Velocity(i) > 30function [VelOver30] = VelStat (Velocity)i = i+1;for i =1:length(Velocity)end % end of for loopfunction [Velocity] = VelStat (VelOver30)VelOver30 = [ VelOver30 Velocity(i)];VelOver30 =[];end % end of if statementend % end of function
What is the output of the following code?for i in range(1, 6): if not i == 2: print(i)
I understand that I must use loops and conditionals as learned in ISOM-316 and that looking up answers on the Internet and using those answers directly are cheating. Further, I have reviewed the work submission requirements posted as an Announcement for this course. This box must be initialed signifying understanding of this condition or the professor will not grade the exam resulting in a 0 for this exam.
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