Question19 Given fruits = ['apple', 'banana', 'cherry', 'date'], which statement replaces 'cherry' with 'mango' in the list? Select one alternative: fruits[2] = 'mango' fruits[3] = 'mango' fruits.remove('mango') fruits.insert(3, 'mango') ResetMaximum marks: 2 Flag question undefined

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BlackTom AI · Accepted Answer

Let's break down what each option would do given fruits = ['apple', 'banana', 'cherry', 'date'].

Option 1: fruits[2] = 'mango'
- This directly targets the element at index 2 (Python uses 0-based indexing). Index 2 currently holds 'cherry'. Replacing it with 'mango' changes the list to ['apple', 'banana', 'mango', 'date']. This achieves the replacement of 'cherry' with 'mango' exactly where it lies.

Option 2: fruits[3] = 'mango'
- Here, index 3 corresponds to 'date'. Assigning 'mango' to that position would produce ['apple', 'banana', 'cherry', 'mango'], which replaces 'date' rather than 'cherry'. So this does not replace 'cherry'.

Option 3: fruits.remove('mango')
- The remove method searches for the value 'mango' in the list and removes the first occurrence. Since the initial list does not contain 'mango' at all, this operation would raise a ValueError indicating that 'mango' is not in the list. It does not modify 'cherry' or achieve the replacement.

Option 4: fruits.insert(3, 'mango')
- The insert method adds a new element at the specified index without removing any existing elements. Inserting at index 3 would place 'mango' before the current element at index 3 ('date'), resulting in ['apple', 'banana', 'cherry', 'mango', 'date']. This leaves 'cherry' intact and adds a new 'mango', not a replacement.

Overall, Option 1 is the operation that replaces the element 'cherry' with 'mango' at the correct position, while the other options either modify a different element, raise an exception, or insert without removing the original.

Question19 Given fruits = ['apple', 'banana', 'cherry', 'date'], which statement replaces 'cherry' with 'mango' in the list? Select one alternative: fruits[2] = 'mango' fruits[3] = 'mango' fruits.remove('mango') fruits.insert(3, 'mango') ResetMaximum marks: 2 Flag question undefined

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