题目
题目
简答题

Let [math: f(x)=x2sin⁡(x)]f(x) = x^2 \sin(x) and let [math: xn=1/n]x_n=1/n. What is the limit of the sequence [math: {f(xn)}]\{f(x_n)\}?

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思路分析
We are given f(x) = x^2 sin(x) and x_n = 1/n, and we want the limit of f(x_n) as n → ∞. First, substitute x_n into f: f(x_n) = (1/n)^2 · ......Login to view full explanation

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