题目
题目
简答题

Let [math: f(x)=x2]f(x) = x^2 and [math: xn=2+1/n]x_n=2+1/n.What is the limit of the sequence [math: {f(xn)}]\{f(x_n)\}?

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思路分析
We start by identifying the given functions: f(x) = x^2 and the sequence x_n = 2 + 1/n. Next, we evaluate f at x_n by substitution: f(x_n) = (x_n)^2 = (2 + 1/n)^2.......Login to view full explanation

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