题目

INTRO TO COMPUTER NETWORKS (CS_372_400_U2025) Module 4 Summary Exercises

多重下拉选择题

For the IPv4 CIDR address 146.10.150.116 /24 What is the... Netmask: [ Select ] 117 256 255 254 0.0.1.255 115 146.10.149.0 0.0.0.255 255.255.254.0 255.255.255.0 146.10.150.0 146.10.151.0 255.255.255.128 146.10.150.116 116 146.10.150.255 Network Address: 146.10.150.0 Host Mask: [ Select ] 0.0.0.255 0.0.1.255 256 255.255.255.0 255 116 117 146.10.151.0 146.10.150.0 254 255.255.254.0 115 255.255.255.128 146.10.150.255 146.10.150.116 146.10.149.0 Broadcast Address: [ Select ] 256 146.10.150.255 255.255.255.0 117 146.10.149.0 255.255.255.128 0.0.1.255 115 116 255 146.10.150.0 146.10.151.0 254 255.255.254.0 0.0.0.255 146.10.150.116 Number of possible hosts: [ Select ] 255.255.255.128 256 115 117 146.10.151.0 254 255 146.10.149.0 146.10.150.255 146.10.150.0 0.0.1.255 0.0.0.255 255.255.254.0 146.10.150.116 116 255.255.255.0 Host Number: [ Select ] 255.255.255.128 146.10.150.255 116 0.0.0.255 0.0.1.255 146.10.150.116 115 255.255.255.0 254 117 146.10.151.0 255 256 146.10.150.0 255.255.254.0 146.10.149.0

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标准答案

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思路分析

The task presents a IPv4 CIDR calculation scenario for 146.10.150.116 /24 and asks to fill in several fields. Below I analyze each field and the provided selections, explaining why the chosen value is correct and why plausible alternatives would be inaccurate. Netmask: The correct netmask for a /24 prefix is 255.255.255.0. This netmask means the first 24 bits are the network portion and the last 8 bits identify hosts within that network. If you encounter other options like 255.255.254.0 (whic......Login to view full explanation