Question at position 20 Consider the following class definition: class MyClass: def __init__(self, value): self.value = value def show_value(): print(self.value) What is likely to happen when calling MyClass(10).show_value()? It prints 10. It calls the method without error and returns None.TypeError raised because self is missing in show_value() method definition.It prints self.value as a string.Clear my selection

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BlackTom AI · Accepted Answer

Consider the given class definition and the call sequence. The method show_value is declared as def show_value(): with no parameters. When accessed as an instance method, Python automatically passes the instance as the first argument (self) to the function. Because show_value is defined without a parameter to receive that self argument, calling MyClass(10).show_value() results in a TypeError indicating a mismatch in the expected number of arguments.

Option 1: It prints 10. This would be true if show_value properly accepted self and printed the stored value, but the actual definition omits self, so a print cannot occur. The error prevents any printing from happening.

Option 2: It calls the method without error and returns None. This is incorrect because Python will raise an exception due to the missing self parameter, so there is neither a successful call nor a normal return of None.

Option 3: TypeError raised because self is missing in show_value() method definition. This directly identifies the root cause: the method signature lacks the required self parameter, causing a TypeError when the bound method is invoked.

Option 4: It prints self.value as a string. This is a misconception: even if the method were defined with self and printed self.value, the value would be printed as an integer (10) unless explicitly converted to a string, but the actual behavior here is an error before any printing can occur.

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