Which statement correctly tests if the user entered the letter Y?

Question

BlackTom AI · Accepted Answer

To determine which statement correctly tests if the user entered the letter Y, we need to look at the syntax used for equality checks and the exact string being compared.
Option 1: 'if userInput = "y" :'. Here, a single equals sign '=' is used, which in most programming languages denotes assignment rather than comparison. This would attempt to assign the value 'y' to userInput, not compare it. This makes the condition invalid for testing equality.
Option 2: 'if userInput = "Y" :'. Like the first option, this uses a single '=' for assignment instead of a comparison operator. It also compares to the string 'Y' but the fundamental issue is the wrong operator, so this cannot correctly test for equality.
Option 3: 'if userInput == "Y" :'. This uses a double equals '==', which is the typical equality comparison operator in many languages (including Python). It also compares against the exact string "Y". This is the correct pattern for testing whether the input matches the uppercase letter Y.
Option 4: 'if userInput == "y" :'. This uses '==' correctly but compares to the lowercase 'y'. If the user actually enters uppercase 'Y', this condition would evaluate to false due to case sensitivity. It would fail to detect the intended input when the user types 'Y'.

Fal25_CS003C_74229 Ch. 3 Pre-Quiz (Remotely Proctored)

Which statement correctly tests if the user entered the letter Y?

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