Consider the following code segment:
c = 2
b = 1
if b == 0 :
c = c + 1
else :
c = c - 1
print(c)

What value is printed by this code segment?

Question

Consider the following code segment:
c = 2
b = 1
if b == 0 :
   c = c + 1
else :
   c = c - 1
print(c)

What value is printed by this code segment?

BlackTom AI · Accepted Answer

We start by tracing the given code step by step to understand how the variables change.
Initial values: c = 2, b = 1.
The conditional checks: if b == 0. Since b is 1, this condition is false, so the code executes the else block.
In the else block, c is updated with c = c - 1. With the current c = 2, this becomes c = 2 - 1 = 1.
After the if-else construct, the next line is print(c), which outputs the current value of c, namely 1.
Now let's evaluate each answer option against this reasoning:
Option 1: 1 — This matches the final value of c after the else branch, so it aligns with the execution.
Option 2: 2 — This would be the original value of c before any modification; it would be correct only if no changes occurred to c, which is not the case here due to the else block updating c.
Option 3: 3 — This would require c to be incremented twice or to start at a higher value; neither happens in the given code segment, so this is incorrect.
Option 4: 4 — This would require an even larger change to c that is not present in the code; the operation performed is a single subtraction, not a sequence leading to 4.
Thus, the reasoning shows why each option corresponds (or does not) to the actual program behavior, focusing on how the conditional directs execution and how c is updated in the else branch.

Fal25_CS003C_74229 Ch. 3 Pre-Quiz (Remotely Proctored)

Consider the following code segment: c = 2 b = 1 if b == 0 : c = c + 1 else : c = c - 1 print(c) What value is printed by this code segment?

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