What is the result of the expression `((addN 10) 20)` in Scheme?
where : (define (addN n) (lambda (m) (+ m n)))

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BlackTom AI · Accepted Answer

The question presents a Scheme expression: ((addN 10) 20) along with a function definition: (define (addN n) (lambda (m) (+ m n))).
First, understand what addN does: it takes an argument n and returns a new function (a lambda) that takes a parameter m and computes (+ m n). This is a simple closure that binds n to the value supplied when addN is called.
Next, evaluate the outer expression step by step:
- Evaluate (addN 10). This calls addN with n bound to 10 and yields a new function: (lambda (m) (+ m 10)).
- Now apply this resulting function to 20 via the call ((addN 10) 20). Substituting m with 20 in the lambda, we get (+ 20 10).
- Compute (+ 20 10), which equals 30.
A few potential points of confusion to watch for:
- If you misinterpret as adding 10 to the literal string or list, that would be incorrect; the operation is numeric addition.
- If you think addN ignores its argument or returns a constant, that would miss the closure behavior where n is captured from the outer call.
- If you forget that the inner function expects the argument m, you might misplace the operands in the addition.
In summary, the result comes from the closure capturing the value 10 as n and then adding it to the provided argument 20, yielding 30.

Section Merge: Merged CMPSC 461(SP 25) Micro learning Quiz 3

What is the result of the expression `((addN 10) 20)` in Scheme? where : (define (addN n) (lambda (m) (+ m n)))

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