What would disrupt the conditions required for Hardy-Weinberg equilibrium?

Question

BlackTom AI · Accepted Answer

Question restatement: What would disrupt the conditions required for Hardy-Weinberg equilibrium?

Option 1: Absence of selection pressure. In Hardy-Weinberg equilibrium, one of the conditions is that there is no natural selection acting on the alleles. If there is an absence of selection pressure, that condition is satisfied, not disrupted. Therefore this option does not cause disruption and is not the correct choice.

Option 2: Random mating. Random mating is another key condition of Hardy-Weinberg equilibrium. When individuals mate randomly, allele combinations are redistributed according to genotype frequencies, maintaining equilibrium. Thus, random mating would not disrupt the equilibrium; it supports it.

Option 3: Small population size. This is a classic disruptor of Hardy-Weinberg equilibrium. In small populations, genetic drift can cause random fluctuations in allele frequencies from generation to generation, leading to deviations from the expected p^2, 2pq, q^2 proportions. This violates the large-population assumption and is a primary source of disruption to equilibrium.

Option 4: Absence of mutations. If there are no mutations, the genetic variation is not being introduced anew, which aligns with one of the equilibrium conditions. While insufficient mutations per se may not always cause immediate disruption, the absence of mutations does not inherently disrupt Hardy-Weinberg equilibrium; it simply maintains the existing alleles without creating new ones. Therefore this option does not describe a disruptor.

Summary: Among the options, only small population size introduces genetic drift that alters allele frequencies and breaks the conditions required for Hardy-Weinberg equilibrium, making it the correct disruptor to note.

AGRI10051_2025_SM2 Supplementary or Special Exam: Genetics for Agriculture (AGRI10051_2025_SM2)- Requires Respondus LockDown Browser

What would disrupt the conditions required for Hardy-Weinberg equilibrium?

查看解析

登录即可查看完整答案

类似问题

You are researching a population of 100 cows, where 91 of them are grey and 9 are black. You know that black colour is a recessive trait for this type of cow. Using the Hardy-Weinberg Equilibrium equation (p2 + 2pq + q2 = 1), what number would be heterozygous?

Assuming the population is in Hardy-Weinberg equilibrium, if 16% of the individuals in a population show a recessive trait (q2=16%), what is the allelic frequency for the dominant allele?

What occurs to allele frequencies when a population is at Hardy-Weinberg equilibrium?

The allele for brown eyes (B) is found within a population at a frequency of 0.7; the allele for blue eyes (b) at a frequency of 0.3. If the conditions for Hardy-Weinberg equilibrium are satisfied, what will be the expected frequency of heterozygous (Bb) individuals?

Which of these would support a population remaining at genetic equilibrium / NOT evolving? (In other words, which of these would not cause a population to evolve?)

Which of the following factors would cause a population to deviate from Hardy–Weinberg equilibrium?

What occurs to allele frequencies when a population is at Hardy-Weinberg equilibrium?

You are researching a population of 100 cows, where 91 of them are grey and 9 are black. You know that the black colour is a recessive trait for this type of cows. Using the Hardy-Weinberg Equilibrium equation (p2+ 2pq + q2 = 1), what number would be heterozygous?

更多留学生实用工具

考试浏览器助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单