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题目
题目

CHM-1020-LD01.2025SU Problem Set 4-Nuclear Chemistry

单项选择题

    If pure polonium-210 (k = 5.02 × 10−3 day−1) were used in a crime, based on radioactive disintegration alone, how long would it take for half the original isotope to disappear?  

选项
A.138 days
B.1.44 × 103 minutes
C.2.9 years
D.210 years
E.69.3 hours
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标准答案
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思路分析
To tackle this problem, I’ll start by identifying the relationship between the decay constant k and the half-life t1/2. The rules of radioactive decay tell us t1/2 = ln(2) / k, where ln(2) is approximately 0.693. Option 1: 138 days. If we plug k = 5.02 × 10^−3 day^−1 into t1/2 = 0.693 / k, we get t1/2 ≈ 0.693 / 0.00502 ≈ 138.0 days. This matches the standard ......Login to view full explanation

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