Question at position 20 If a parent cell has alleles AABb, how many gamete variations will be produced as a result of independent assortment? Enter the number.AnswerIf a parent cell has alleles AABb, how many gamete variations will be produced as a result of independent assortment? Enter the number.[input]

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BlackTom AI · Accepted Answer

First, restate the problem to clarify what is being asked: a parent cell has alleles AABb, and we want the number of gamete variations produced by independent assortment.
Since independent assortment applies to different gene loci, we look at each gene separately in this genotype. For the A locus, the parent has AA, which means there is no variation at this locus among gametes because both copies are the same allele. For the B locus, the parent is Bb, which is heterozygous and can produce two different alleles in the gametes: B and b.
To form gametes, we combine one allele from each locus. Because A is always A, the only variable contribution comes from the B locus, giving two possible gametes: AB and Ab. The B and b alleles pair with the fixed A allele, so there are two distinct gamete types overall.
It is important not to confuse this with a scenario where both loci are heterozygous or where more loci provide variation; here, the A locus does not contribute to variation due to homozygosity (AA).
If you were thinking about a general rule, the number of gamete variations is the product of the number of distinct alleles at each independently assorting locus. Here that would be (1 option for A) × (2 options for B) = 2 variations, reflecting the two possible B allele contributions combined with the constant A.
Note that there are no alternate options provided in the prompt, so the explanation focuses on deriving the number from the given genotype rather than selecting from multiple choices.

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