Given a list values that contains the first ten prime numbers, which statement does NOT print each element in the list?

Question

BlackTom AI · Accepted Answer

Question context: We have a list named values containing the first ten prime numbers, and we are evaluating which given loop would fail to print every element in that list.

Option 1 (A): 'for i in range(len(values)) : print(values[i])' 
- This loop sets i to 0 up to len(values)-1, accessing values[i] for each valid index. Since Python lists are 0-indexed, this prints every element exactly once. This option correctly prints all elements.

Option 2 (B): 'for element in values : print(element)' 
- This uses direct iteration over the list elements themselves, not indices. It prints each element in the list exactly once, so all elements are printed. This option also correctly prints all elements.

Option 3 (C): 'for i in range(0, len(values)) : print(values[i])' 
- Here, range(0, len(values)) generates 0 through len(values)-1, inclusive of 0. Accessing values[i] for each i covers every index in the list, so all elements are printed. This option correctly prints all elements.

Option 4 (D): 'for i in range(1, len(values)) : print(values[i])' 
- This loop starts i at 1 and goes up to len(values)-1. It prints values[1], values[2], ..., values[len(values)-1], thereby skipping the element at index 0 (the first element) entirely. As a result, not every element is printed. This option is the one that does not print each element in the list.

Summary of why the non-print-all option stands out: The common feature of options A, B, and C is that they cover all indices or all elements, ensuring every item is printed. The differentiating factor is starting index; starting at 1 omits the first element, which violates the requirement to print every element.

Fal25_CS003C_74229 Ch. 6 Pre-Quiz (Remotely Proctored)

Given a list values that contains the first ten prime numbers, which statement does NOT print each element in the list?

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