Radioactive decay exhibits

Question

BlackTom AI · Accepted Answer

The question presents: 'Radioactive decay exhibits' with multiple choices. 
Option 1: 'first-order kinetics.' This is correct because radioactive decay follows a first-order kinetic process, where the rate is proportional to the number of undecayed nuclei, leading to a constant half-life regardless of amount present.
Option 2: 'second-order kinetics.' This would imply the rate depends on the square of the remaining quantity or on the product of two species, which does not describe simple radioactive decay dynamics. 
Option 3: '1/2-th order kinetics.' This is not a recognized kinetic category in standard chemical kinetics; half-order is a rare, specialized case, not applicable to straightforward nuclear decay. 
Option 4: 'third-order kinetics.' This would require the rate law to be proportional to the cube of the concentration or to a combination of terms, which does not fit the decay behavior of nuclei. 
Option 5: 'zeroth-order kinetics.' Zeroth-order would mean a constant rate independent of the amount present, which contradicts the observed proportional decrease in activity over time for a closed population of nuclei. 
In summary, only first-order kinetics aligns with the fundamental description of radioactive decay, while the other orders conflict with the standard decay model and its dependence on the remaining number of undecayed nuclei.

CHM-1020-LD01.2025SU Problem Set 4-Nuclear Chemistry

Radioactive decay exhibits

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